(1/5)=5^2c+3

Solution for (1/5)=5^2c+3 equation:

(1/5)=5^2c+3

We move all terms to the left:

(1/5)-(5^2c+3)=0

We add all the numbers together, and all the variables

-(5^2c+3)+(+1/5)=0

We get rid of parentheses

-5^2c-3+1/5=0

We multiply all the terms by the denominator


-5^2c*5+1-3*5=0

We add all the numbers together, and all the variables

-5^2c*5-14=0

Wy multiply elements

-25c^2-14=0

a = -25; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·(-25)·(-14)
Δ = -1400
Delta is less than zero, so there is no solution for the equation